j-10(1-j)=-7(j-2)

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Solution for j-10(1-j)=-7(j-2) equation: 



j-10(1-j)=-7(j-2)

We move all terms to the left:

j-10(1-j)-(-7(j-2))=0

We add all the numbers together, and all the variables

j-10(-1j+1)-(-7(j-2))=0

We multiply parentheses

j+10j-(-7(j-2))-10=0



We calculate terms in parentheses: -(-7(j-2)), so:

-7(j-2)

We multiply parentheses

-7j+14

Back to the equation:

-(-7j+14)



We add all the numbers together, and all the variables

11j-(-7j+14)-10=0

We get rid of parentheses

11j+7j-14-10=0

We add all the numbers together, and all the variables

18j-24=0

We move all terms containing j to the left, all other terms to the right

18j=24

j=24/18

j=1+1/3

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