j-2(1-2)=3(j-3)+5

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Solution for j-2(1-2)=3(j-3)+5 equation: 


Simplifying
j + -2(1 + -2) = 3(j + -3) + 5

Combine like terms: 1 + -2 = -1
j + -2(-1) = 3(j + -3) + 5

Multiply -2 * -1
j + 2 = 3(j + -3) + 5

Reorder the terms:
2 + j = 3(j + -3) + 5

Reorder the terms:
2 + j = 3(-3 + j) + 5
2 + j = (-3 * 3 + j * 3) + 5
2 + j = (-9 + 3j) + 5

Reorder the terms:
2 + j = -9 + 5 + 3j

Combine like terms: -9 + 5 = -4
2 + j = -4 + 3j

Solving
2 + j = -4 + 3j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-3j' to each side of the equation.
2 + j + -3j = -4 + 3j + -3j

Combine like terms: j + -3j = -2j
2 + -2j = -4 + 3j + -3j

Combine like terms: 3j + -3j = 0
2 + -2j = -4 + 0
2 + -2j = -4

Add '-2' to each side of the equation.
2 + -2 + -2j = -4 + -2

Combine like terms: 2 + -2 = 0
0 + -2j = -4 + -2
-2j = -4 + -2

Combine like terms: -4 + -2 = -6
-2j = -6

Divide each side by '-2'.
j = 3

Simplifying
j = 3

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