j-2(1-2j)=3(j-3)+5

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Solution for j-2(1-2j)=3(j-3)+5 equation:


Simplifying
j + -2(1 + -2j) = 3(j + -3) + 5
j + (1 * -2 + -2j * -2) = 3(j + -3) + 5
j + (-2 + 4j) = 3(j + -3) + 5

Reorder the terms:
-2 + j + 4j = 3(j + -3) + 5

Combine like terms: j + 4j = 5j
-2 + 5j = 3(j + -3) + 5

Reorder the terms:
-2 + 5j = 3(-3 + j) + 5
-2 + 5j = (-3 * 3 + j * 3) + 5
-2 + 5j = (-9 + 3j) + 5

Reorder the terms:
-2 + 5j = -9 + 5 + 3j

Combine like terms: -9 + 5 = -4
-2 + 5j = -4 + 3j

Solving
-2 + 5j = -4 + 3j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-3j' to each side of the equation.
-2 + 5j + -3j = -4 + 3j + -3j

Combine like terms: 5j + -3j = 2j
-2 + 2j = -4 + 3j + -3j

Combine like terms: 3j + -3j = 0
-2 + 2j = -4 + 0
-2 + 2j = -4

Add '2' to each side of the equation.
-2 + 2 + 2j = -4 + 2

Combine like terms: -2 + 2 = 0
0 + 2j = -4 + 2
2j = -4 + 2

Combine like terms: -4 + 2 = -2
2j = -2

Divide each side by '2'.
j = -1

Simplifying
j = -1

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