j-6=(1/2)j+3

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Solution for j-6=(1/2)j+3 equation: 



j-6=(1/2)j+3

We move all terms to the left:

j-6-((1/2)j+3)=0



Domain of the equation: 2)j+3)!=0

j!=0/1

j!=0

j∈R



We add all the numbers together, and all the variables

j-((+1/2)j+3)-6=0

We multiply all the terms by the denominator


j*2)j+3)-((-6*2)j+3)+1=0

We add all the numbers together, and all the variables

j*2)j+3)-((-12)j+3)+1=0

Wy multiply elements

2j^2-12)j+3)+1=0

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