j-6=(j/2)+3

Solution for j-6=(j/2)+3 equation:

j-6=(j/2)+3

We move all terms to the left:

j-6-((j/2)+3)=0

We add all the numbers together, and all the variables

j-((+j/2)+3)-6=0

We multiply all the terms by the denominator


j*2)+3)-((+j-6*2)+3)=0

We add all the numbers together, and all the variables

j*2)+3)-((j-12)+3)=0

We add all the numbers together, and all the variables

j*2)+3)-((j=0

Wy multiply elements

2j^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$j=\frac{-b}{2a}=\frac{0}{4}=0$