j-6=1/2-j+3

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Solution for j-6=1/2-j+3 equation: 



j-6=1/2-j+3

We move all terms to the left:

j-6-(1/2-j+3)=0



Domain of the equation: 2-j+3)!=0

We move all terms containing j to the left, all other terms to the right

-j+3)!=-2

j∈R



We add all the numbers together, and all the variables

j-(-1j+1/2+3)-6=0

We get rid of parentheses

j+1j-3-6-1/2=0

We multiply all the terms by the denominator


j*2+1j*2-1-3*2-6*2=0

We add all the numbers together, and all the variables

j*2+1j*2-19=0

Wy multiply elements

2j+2j-19=0

We add all the numbers together, and all the variables

4j-19=0

We move all terms containing j to the left, all other terms to the right

4j=19

j=19/4

j=4+3/4

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