j/10-(-27)=32

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Solution for j/10-(-27)=32 equation:



j/10-(-27)=32
We move all terms to the left:
j/10-(-27)-(32)=0
determiningTheFunctionDomain j/10-32-(-27)=0
We add all the numbers together, and all the variables
j/10-5=0
We multiply all the terms by the denominator
j-5*10=0
We add all the numbers together, and all the variables
j-50=0
We move all terms containing j to the left, all other terms to the right
j=50

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