j/3+35=40

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Solution for j/3+35=40 equation: 



j/3+35=40

We move all terms to the left:

j/3+35-(40)=0

We add all the numbers together, and all the variables

j/3-5=0

We multiply all the terms by the denominator


j-5*3=0

We add all the numbers together, and all the variables

j-15=0

We move all terms containing j to the left, all other terms to the right

j=15

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