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j/6=(1/3)
We move all terms to the left:
j/6-((1/3))=0
We add all the numbers together, and all the variables
j/6-((+1/3))=0
We calculate fractions
3j^2/()+()/()=0
We add all the numbers together, and all the variables
3j^2/()+1=0
We multiply all the terms by the denominator
3j^2+1*()=0
We add all the numbers together, and all the variables
3j^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$j=\frac{-b}{2a}=\frac{0}{6}=0$
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