k(-7/2)=23/5

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Solution for k(-7/2)=23/5 equation: 



k(-7/2)=23/5

We move all terms to the left:

k(-7/2)-(23/5)=0

We add all the numbers together, and all the variables

k(-7/2)-(+23/5)=0

We multiply parentheses

-7k^2-(+23/5)=0

We get rid of parentheses

-7k^2-23/5=0

We multiply all the terms by the denominator


-7k^2*5-23=0

Wy multiply elements

-35k^2-23=0

a = -35; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·(-35)·(-23)
Δ = -3220
Delta is less than zero, so there is no solution for the equation

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