k(1+2a+3b)=

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Solution for k(1+2a+3b)= equation: 


Simplifying
k(1 + 2a + 3b) = 0
(1 * k + 2a * k + 3b * k) = 0

Reorder the terms:
(2ak + 3bk + 1k) = 0
(2ak + 3bk + 1k) = 0

Solving
2ak + 3bk + 1k = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3bk' to each side of the equation.
2ak + 3bk + -3bk + 1k = 0 + -3bk

Combine like terms: 3bk + -3bk = 0
2ak + 0 + 1k = 0 + -3bk
2ak + 1k = 0 + -3bk
Remove the zero:
2ak + 1k = -3bk

Add '-1k' to each side of the equation.
2ak + 1k + -1k = -3bk + -1k

Combine like terms: 1k + -1k = 0
2ak + 0 = -3bk + -1k
2ak = -3bk + -1k

Divide each side by '2k'.
a = -1.5b + -0.5

Simplifying
a = -1.5b + -0.5

Reorder the terms:
a = -0.5 + -1.5b

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