k(15k+1)+28=0

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Solution for k(15k+1)+28=0 equation: 



k(15k+1)+28=0

We multiply parentheses

15k^2+k+28=0

a = 15; b = 1; c = +28;
Δ = b2-4ac
Δ = 12-4·15·28
Δ = -1679
Delta is less than zero, so there is no solution for the equation

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