k(4-3k)=28

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Solution for k(4-3k)=28 equation: 



k(4-3k)=28

We move all terms to the left:

k(4-3k)-(28)=0

We add all the numbers together, and all the variables

k(-3k+4)-28=0

We multiply parentheses

-3k^2+4k-28=0

a = -3; b = 4; c = -28;
Δ = b2-4ac
Δ = 42-4·(-3)·(-28)
Δ = -320
Delta is less than zero, so there is no solution for the equation

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