k(a+1)=5z+5

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Solution for k(a+1)=5z+5 equation:


Simplifying
k(a + 1) = 5z + 5

Reorder the terms:
k(1 + a) = 5z + 5
(1 * k + a * k) = 5z + 5

Reorder the terms:
(ak + 1k) = 5z + 5
(ak + 1k) = 5z + 5

Reorder the terms:
ak + 1k = 5 + 5z

Solving
ak + 1k = 5 + 5z

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1k' to each side of the equation.
ak + 1k + -1k = 5 + -1k + 5z

Combine like terms: 1k + -1k = 0
ak + 0 = 5 + -1k + 5z
ak = 5 + -1k + 5z

Divide each side by 'k'.
a = 5k-1 + -1 + 5k-1z

Simplifying
a = 5k-1 + -1 + 5k-1z

Reorder the terms:
a = -1 + 5k-1 + 5k-1z

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