k(k-2)=2(k-9)

Solution for k(k-2)=2(k-9) equation:

k(k-2)=2(k-9)

We move all terms to the left:

k(k-2)-(2(k-9))=0

We multiply parentheses

k^2-2k-(2(k-9))=0


We calculate terms in parentheses: -(2(k-9)), so:

2(k-9)

We multiply parentheses

2k-18

Back to the equation:

-(2k-18)


We get rid of parentheses

k^2-2k-2k+18=0

We add all the numbers together, and all the variables

k^2-4k+18=0

a = 1; b = -4; c = +18;
Δ = b2-4ac
Δ = -42-4·1·18
Δ = -56
Delta is less than zero, so there is no solution for the equation