k(y+3z)=4(y-5)

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Solution for k(y+3z)=4(y-5) equation:


Simplifying
k(y + 3z) = 4(y + -5)
(y * k + 3z * k) = 4(y + -5)
(ky + 3kz) = 4(y + -5)

Reorder the terms:
ky + 3kz = 4(-5 + y)
ky + 3kz = (-5 * 4 + y * 4)
ky + 3kz = (-20 + 4y)

Solving
ky + 3kz = -20 + 4y

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Reorder the terms:
20 + ky + 3kz + -4y = -20 + 4y + 20 + -4y

Reorder the terms:
20 + ky + 3kz + -4y = -20 + 20 + 4y + -4y

Combine like terms: -20 + 20 = 0
20 + ky + 3kz + -4y = 0 + 4y + -4y
20 + ky + 3kz + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
20 + ky + 3kz + -4y = 0

The solution to this equation could not be determined.

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