k(y+3z)=4(y-5)fory

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Solution for k(y+3z)=4(y-5)fory equation: 


Simplifying
k(y + 3z) = 4(y + -5) * fory
(y * k + 3z * k) = 4(y + -5) * fory
(ky + 3kz) = 4(y + -5) * fory

Reorder the terms:
ky + 3kz = 4(-5 + y) * fory

Reorder the terms for easier multiplication:
ky + 3kz = 4fory(-5 + y)
ky + 3kz = (-5 * 4fory + y * 4fory)
ky + 3kz = (-20fory + 4fory2)

Solving
ky + 3kz = -20fory + 4fory2

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Reorder the terms:
20fory + -4fory2 + ky + 3kz = -20fory + 4fory2 + 20fory + -4fory2

Reorder the terms:
20fory + -4fory2 + ky + 3kz = -20fory + 20fory + 4fory2 + -4fory2

Combine like terms: -20fory + 20fory = 0
20fory + -4fory2 + ky + 3kz = 0 + 4fory2 + -4fory2
20fory + -4fory2 + ky + 3kz = 4fory2 + -4fory2

Combine like terms: 4fory2 + -4fory2 = 0
20fory + -4fory2 + ky + 3kz = 0

The solution to this equation could not be determined.

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