k(y+3z)=r(y-5)

Solution for k(y+3z)=r(y-5) equation:

Simplifying
k(y + 3z) = r(y + -5)
(y * k + 3z * k) = r(y + -5)
(ky + 3kz) = r(y + -5)

Reorder the terms:
ky + 3kz = r(-5 + y)
ky + 3kz = (-5 * r + y * r)
ky + 3kz = (-5r + ry)

Solving
ky + 3kz = -5r + ry

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Reorder the terms:
ky + 3kz + 5r + -1ry = -5r + 5r + ry + -1ry

Combine like terms: -5r + 5r = 0
ky + 3kz + 5r + -1ry = 0 + ry + -1ry
ky + 3kz + 5r + -1ry = ry + -1ry

Combine like terms: ry + -1ry = 0
ky + 3kz + 5r + -1ry = 0

The solution to this equation could not be determined.