k+(k+1)+(k+2)=4

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Solution for k+(k+1)+(k+2)=4 equation: 



k+(k+1)+(k+2)=4

We move all terms to the left:

k+(k+1)+(k+2)-(4)=0

We get rid of parentheses

k+k+k+1+2-4=0

We add all the numbers together, and all the variables

3k-1=0

We move all terms containing k to the left, all other terms to the right

3k=1

k=1/3

k=1/3

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