k+(k=1)+(K+2)=4k

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Solution for k+(k=1)+(K+2)=4k equation: 



k+(k=1)+(+2)=4k

We move all terms to the left:

k+(k-(1)+(+2))=0

We add all the numbers together, and all the variables

k+(k-1+2)=0

We get rid of parentheses

k+k-1+2=0

We add all the numbers together, and all the variables

2k+1=0

We move all terms containing k to the left, all other terms to the right

2k=-1

k=-1/2

k=-1/2

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