k+1/k=2

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Solution for k+1/k=2 equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

k+1/k = 2 // - 2

k+1/k-2 = 0

1*k^1+1*k^-1-2*k^0 = 0

(1*k^2-2*k^1+1*k^0)/(k^1) = 0 // * k^2

k^1*(1*k^2-2*k^1+1*k^0) = 0

k^1

k^2-2*k+1 = 0

k^2-2*k+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

k = 2/(1*2)

k = 1 or k = 1

k in { 1, 1} 

k in { 1, 1 }

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