k+2(k-3)=2(4k+3)+3

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Solution for k+2(k-3)=2(4k+3)+3 equation:



k+2(k-3)=2(4k+3)+3
We move all terms to the left:
k+2(k-3)-(2(4k+3)+3)=0
We multiply parentheses
k+2k-(2(4k+3)+3)-6=0
We calculate terms in parentheses: -(2(4k+3)+3), so:
2(4k+3)+3
We multiply parentheses
8k+6+3
We add all the numbers together, and all the variables
8k+9
Back to the equation:
-(8k+9)
We add all the numbers together, and all the variables
3k-(8k+9)-6=0
We get rid of parentheses
3k-8k-9-6=0
We add all the numbers together, and all the variables
-5k-15=0
We move all terms containing k to the left, all other terms to the right
-5k=15
k=15/-5
k=-3

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