k+2(k-3)=2(4k+3)=k

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Solution for k+2(k-3)=2(4k+3)=k equation:



k+2(k-3)=2(4k+3)=k
We move all terms to the left:
k+2(k-3)-(2(4k+3))=0
We multiply parentheses
k+2k-(2(4k+3))-6=0
We calculate terms in parentheses: -(2(4k+3)), so:
2(4k+3)
We multiply parentheses
8k+6
Back to the equation:
-(8k+6)
We add all the numbers together, and all the variables
3k-(8k+6)-6=0
We get rid of parentheses
3k-8k-6-6=0
We add all the numbers together, and all the variables
-5k-12=0
We move all terms containing k to the left, all other terms to the right
-5k=12
k=12/-5
k=-2+2/5

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