k+2(k-3)=2(4k+3)=k

Solution for k+2(k-3)=2(4k+3)=k equation:

k+2(k-3)=2(4k+3)=k

We move all terms to the left:

k+2(k-3)-(2(4k+3))=0

We multiply parentheses

k+2k-(2(4k+3))-6=0


We calculate terms in parentheses: -(2(4k+3)), so:

2(4k+3)

We multiply parentheses

8k+6

Back to the equation:

-(8k+6)


We add all the numbers together, and all the variables

3k-(8k+6)-6=0

We get rid of parentheses

3k-8k-6-6=0

We add all the numbers together, and all the variables

-5k-12=0

We move all terms containing k to the left, all other terms to the right

-5k=12

k=12/-5

k=-2+2/5