k+20=4(k+2)

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Solution for k+20=4(k+2) equation: 



k+20=4(k+2)

We move all terms to the left:

k+20-(4(k+2))=0



We calculate terms in parentheses: -(4(k+2)), so:

4(k+2)

We multiply parentheses

4k+8

Back to the equation:

-(4k+8)



We get rid of parentheses

k-4k-8+20=0

We add all the numbers together, and all the variables

-3k+12=0

We move all terms containing k to the left, all other terms to the right

-3k=-12

k=-12/-3

k=+4

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