k+3(2k-5)=4k-2)-7

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Solution for k+3(2k-5)=4k-2)-7 equation: 



k+3(2k-5)=4k-2)-7

We move all terms to the left:

k+3(2k-5)-(4k-2)-7)=0

We add all the numbers together, and all the variables

k+3(2k-5)-(4k-2)=0

We multiply parentheses

k+6k-(4k-2)-15=0

We get rid of parentheses

k+6k-4k+2-15=0

We add all the numbers together, and all the variables

3k-13=0

We move all terms containing k to the left, all other terms to the right

3k=13

k=13/3

k=4+1/3

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