k+3(2k-5)=4k-2)-7

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Solution for k+3(2k-5)=4k-2)-7 equation:



k+3(2k-5)=4k-2)-7
We move all terms to the left:
k+3(2k-5)-(4k-2)-7)=0
We add all the numbers together, and all the variables
k+3(2k-5)-(4k-2)=0
We multiply parentheses
k+6k-(4k-2)-15=0
We get rid of parentheses
k+6k-4k+2-15=0
We add all the numbers together, and all the variables
3k-13=0
We move all terms containing k to the left, all other terms to the right
3k=13
k=13/3
k=4+1/3

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