If it's not what You are looking for type in the equation solver your own equation and let us solve it.
k+4/3=10
We move all terms to the left:
k+4/3-(10)=0
determiningTheFunctionDomain k-10+4/3=0
We multiply all the terms by the denominator
k*3+4-10*3=0
We add all the numbers together, and all the variables
k*3-26=0
Wy multiply elements
3k-26=0
We move all terms containing k to the left, all other terms to the right
3k=26
k=26/3
k=8+2/3
| 128/x+2x=24 | | -5x=5+x-4x | | -6w-1=-3w-10 | | 16t^2+1156=0 | | 3×+5y+10=0 | | (4x-8)+150=20x-2 | | 3/4x+1-5/4x=7/4 | | t+6/3=2/3 | | 7/3x+9-4=5/x+3 | | (15x-43)=(8x+18) | | 8.4=2.4-3b | | 1+9u=8u+9 | | -1/2x+7=3/2x-43 | | 4n+-2=n+8 | | |6x-7|+6=4 | | 0=9x^2-97x+220 | | 9.50x+105=17.75x | | (y+3)^2+y^2=9 | | 6m-3=5m | | 6.4+x+8.3+3.1=x*4 | | 4n-2=n+8 | | 8.x+5=3x-4 | | 19+x+14=195 | | 61-x=14 | | 4x^2+10x=75 | | 7/3x-15=3(x-25)/5+1/15x | | x/3=8/1 | | 7/3x-10-20+40=180 | | 4w-1=5w=37 | | 57=33^x | | 1/3^2+3x-4=-4 | | (y+3)2+y2=9 |