k+6+3k=2(2k+1)+2

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Solution for k+6+3k=2(2k+1)+2 equation: 



k+6+3k=2(2k+1)+2

We move all terms to the left:

k+6+3k-(2(2k+1)+2)=0

We add all the numbers together, and all the variables

4k-(2(2k+1)+2)+6=0



We calculate terms in parentheses: -(2(2k+1)+2), so:

2(2k+1)+2

We multiply parentheses

4k+2+2

We add all the numbers together, and all the variables

4k+4

Back to the equation:

-(4k+4)



We get rid of parentheses

4k-4k-4+6=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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