k+k-6=2(k-3)

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Solution for k+k-6=2(k-3) equation: 



k+k-6=2(k-3)

We move all terms to the left:

k+k-6-(2(k-3))=0

We add all the numbers together, and all the variables

2k-(2(k-3))-6=0



We calculate terms in parentheses: -(2(k-3)), so:

2(k-3)

We multiply parentheses

2k-6

Back to the equation:

-(2k-6)



We get rid of parentheses

2k-2k+6-6=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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