k-3+3(k-2)=2(2k-5)

Solution for k-3+3(k-2)=2(2k-5) equation:

Simplifying
k + -3 + 3(k + -2) = 2(2k + -5)

Reorder the terms:
k + -3 + 3(-2 + k) = 2(2k + -5)
k + -3 + (-2 * 3 + k * 3) = 2(2k + -5)
k + -3 + (-6 + 3k) = 2(2k + -5)

Reorder the terms:
-3 + -6 + k + 3k = 2(2k + -5)

Combine like terms: -3 + -6 = -9
-9 + k + 3k = 2(2k + -5)

Combine like terms: k + 3k = 4k
-9 + 4k = 2(2k + -5)

Reorder the terms:
-9 + 4k = 2(-5 + 2k)
-9 + 4k = (-5 * 2 + 2k * 2)
-9 + 4k = (-10 + 4k)

Add '-4k' to each side of the equation.
-9 + 4k + -4k = -10 + 4k + -4k

Combine like terms: 4k + -4k = 0
-9 + 0 = -10 + 4k + -4k
-9 = -10 + 4k + -4k

Combine like terms: 4k + -4k = 0
-9 = -10 + 0
-9 = -10

Solving
-9 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.