k-6=2(4+k)

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Solution for k-6=2(4+k) equation: 



k-6=2(4+k)

We move all terms to the left:

k-6-(2(4+k))=0

We add all the numbers together, and all the variables

k-(2(k+4))-6=0



We calculate terms in parentheses: -(2(k+4)), so:

2(k+4)

We multiply parentheses

2k+8

Back to the equation:

-(2k+8)



We get rid of parentheses

k-2k-8-6=0

We add all the numbers together, and all the variables

-1k-14=0

We move all terms containing k to the left, all other terms to the right

-k=14

k=14/-1

k=-14

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