k/(k+1)+k/(k-2)=2

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Solution for k/(k+1)+k/(k-2)=2 equation: 


D( k )

k+1 = 0

k-2 = 0

k+1 = 0

k+1 = 0

k+1 = 0 // - 1

k = -1

k-2 = 0

k-2 = 0

k-2 = 0 // + 2

k = 2

k in (-oo:-1) U (-1:2) U (2:+oo)

k/(k+1)+k/(k-2) = 2 // - 2

k/(k+1)+k/(k-2)-2 = 0

(k*(k-2))/((k+1)*(k-2))+(k*(k+1))/((k+1)*(k-2))+(-2*(k+1)*(k-2))/((k+1)*(k-2)) = 0

k*(k-2)+k*(k+1)-2*(k+1)*(k-2) = 0

2*k^2-2*k^2-k+2*k+4 = 0

k+4 = 0

(k+4)/((k+1)*(k-2)) = 0

(k+4)/((k+1)*(k-2)) = 0 // * (k+1)*(k-2)

k+4 = 0

k+4 = 0 // - 4

k = -4

k = -4

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