k/11=3/(k-8)

Solution for k/11=3/(k-8) equation:

D( k )

k-8 = 0

k-8 = 0

k-8 = 0

k-8 = 0 // + 8

k = 8

k in (-oo:8) U (8:+oo)

k/11 = 3/(k-8) // - 3/(k-8)

k/11-(3/(k-8)) = 0

k/11-3*(k-8)^-1 = 0

k/11-3/(k-8) = 0

(-3*11)/(11*(k-8))+(k*(k-8))/(11*(k-8)) = 0

k*(k-8)-3*11 = 0

k^2-8*k-33 = 0

k^2-8*k-33 = 0

k^2-8*k-33 = 0

DELTA = (-8)^2-(-33*1*4)

DELTA = 196

DELTA > 0

k = (196^(1/2)+8)/(1*2) or k = (8-196^(1/2))/(1*2)

k = 11 or k = -3

(k+3)*(k-11) = 0

((k+3)*(k-11))/(11*(k-8)) = 0

((k+3)*(k-11))/(11*(k-8)) = 0 // * 11*(k-8)

(k+3)*(k-11) = 0

( k+3 )

k+3 = 0 // - 3

k = -3

( k-11 )

k-11 = 0 // + 11

k = 11

k in { -3, 11 }