k/11=3/k-8

Solution for k/11=3/k-8 equation:

D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

k/11 = 3/k-8 // - 3/k-8

k/11-(3/k)+8 = 0

k/11-3*k^-1+8 = 0

1/11*k^1-3*k^-1+8*k^0 = 0

(1/11*k^2+8*k^1-3*k^0)/(k^1) = 0 // * k^2

k^1*(1/11*k^2+8*k^1-3*k^0) = 0

k^1

(1/11)*k^2+8*k-3 = 0

(1/11)*k^2+8*k-3 = 0

DELTA = 8^2-(-3*4*(1/11))

DELTA = 716/11

DELTA > 0

k = ((716/11)^(1/2)-8)/(2*(1/11)) or k = (-(716/11)^(1/2)-8)/(2*(1/11))

k = 11/2*((716/11)^(1/2)-8) or k = -11/2*((716/11)^(1/2)+8)

k in { -11/2*((716/11)^(1/2)+8), 11/2*((716/11)^(1/2)-8)} 

k in { -11/2*((716/11)^(1/2)+8), 11/2*((716/11)^(1/2)-8) }