k/4+2(3k-1)/3

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Solution for k/4+2(3k-1)/3 equation:


k in (-oo:+oo)

(2*(3*k-1))/3+k/4 = 0

(2*4*(3*k-1))/(3*4)+(3*k)/(3*4) = 0

2*4*(3*k-1)+3*k = 0

27*k-8 = 0

(27*k-8)/(3*4) = 0

(27*k-8)/(3*4) = 0 // * 3*4

27*k-8 = 0

27*k-8 = 0 // + 8

27*k = 8 // : 27

k = 8/27

k = 8/27

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