k/4=(-17)/2

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Solution for k/4=(-17)/2 equation: 



k/4=(-17)/2

We move all terms to the left:

k/4-((-17)/2)=0

We calculate fractions


2k^2/()+()/()=0

We add all the numbers together, and all the variables

2k^2/()+1=0

We multiply all the terms by the denominator


2k^2+1*()=0

We add all the numbers together, and all the variables

2k^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{4}=0$

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