k2+12=3

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Solution for k2+12=3 equation:



k2+12=3
We move all terms to the left:
k2+12-(3)=0
We add all the numbers together, and all the variables
k^2+9=0
a = 1; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·1·9
Δ = -36
Delta is less than zero, so there is no solution for the equation

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