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k2+13k+30=0
We add all the numbers together, and all the variables
k^2+13k+30=0
a = 1; b = 13; c = +30;
Δ = b2-4ac
Δ = 132-4·1·30
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*1}=\frac{-20}{2} =-10 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*1}=\frac{-6}{2} =-3 $
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