k2+23=984

Solution for k2+23=984 equation:

k2+23=984

We move all terms to the left:

k2+23-(984)=0

We add all the numbers together, and all the variables

k^2-961=0

a = 1; b = 0; c = -961;
Δ = b2-4ac
Δ = 02-4·1·(-961)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-62}{2*1}=\frac{-62}{2}
=-31
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+62}{2*1}=\frac{62}{2}
=31
$