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k2+4k-7=0
We add all the numbers together, and all the variables
k^2+4k-7=0
a = 1; b = 4; c = -7;
Δ = b2-4ac
Δ = 42-4·1·(-7)
Δ = 44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44}=\sqrt{4*11}=\sqrt{4}*\sqrt{11}=2\sqrt{11}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{11}}{2*1}=\frac{-4-2\sqrt{11}}{2} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{11}}{2*1}=\frac{-4+2\sqrt{11}}{2} $
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