k2+k=24

Solution for k2+k=24 equation:

k2+k=24

We move all terms to the left:

k2+k-(24)=0

We add all the numbers together, and all the variables

k^2+k-24=0

a = 1; b = 1; c = -24;
Δ = b2-4ac
Δ = 12-4·1·(-24)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{97}}{2*1}=\frac{-1-\sqrt{97}}{2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{97}}{2*1}=\frac{-1+\sqrt{97}}{2}
$