k2=-35k

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Solution for k2=-35k equation:



k2=-35k
We move all terms to the left:
k2-(-35k)=0
We add all the numbers together, and all the variables
k^2-(-35k)=0
We get rid of parentheses
k^2+35k=0
a = 1; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·1·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*1}=\frac{-70}{2} =-35 $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*1}=\frac{0}{2} =0 $

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