k2=0,49

Solution for k2=0,49 equation:

k2=0.49

We move all terms to the left:

k2-(0.49)=0

We add all the numbers together, and all the variables

k^2-0.49=0

a = 1; b = 0; c = -0.49;
Δ = b2-4ac
Δ = 02-4·1·(-0.49)
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.96}}{2*1}=\frac{0-\sqrt{1.96}}{2}
=-\frac{\sqrt{}}{2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.96}}{2*1}=\frac{0+\sqrt{1.96}}{2}
=\frac{\sqrt{}}{2}
$