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k2=23.201.06
We move all terms to the left:
k2-(23.201.06)=0
We add all the numbers together, and all the variables
k2-(1.39206)=0
We add all the numbers together, and all the variables
k^2-1.39206=0
a = 1; b = 0; c = -1.39206;
Δ = b2-4ac
Δ = 02-4·1·(-1.39206)
Δ = 5.56824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5.56824}}{2*1}=\frac{0-\sqrt{5.56824}}{2} =-\frac{\sqrt{}}{2} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5.56824}}{2*1}=\frac{0+\sqrt{5.56824}}{2} =\frac{\sqrt{}}{2} $
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