k2=4/9

Solution for k2=4/9 equation:

k2=4/9

We move all terms to the left:

k2-(4/9)=0

We add all the numbers together, and all the variables

k2-(+4/9)=0

We add all the numbers together, and all the variables

k^2-(+4/9)=0

We get rid of parentheses

k^2-4/9=0

We multiply all the terms by the denominator


k^2*9-4=0

Wy multiply elements

9k^2-4=0

a = 9; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·9·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*9}=\frac{-12}{18}
=-2/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*9}=\frac{12}{18}
=2/3
$