k=(2x+2)/x

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Solution for k=(2x+2)/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

k = (2*x+2)/x // - (2*x+2)/x

k-((2*x+2)/x) = 0

(-1*(2*x+2))/x+k = 0

(-1*(2*x+2))/x+(k*x)/x = 0

k*x-1*(2*x+2) = 0

k*x-2*x-2 = 0

k*x-2*x-2 = 0

k*x-2 = 0 // + 2

k*x = 2 // : k

x = 2/k

x-2*k^-1 = 0

(x-2*k^-1)/x = 0

(x-2*k^-1)/x = 0 // * x

x-2*k^-1 = 0

x-2*k^-1 = 0 // + -2*k^-1

x = -(-2*k^-1)

x = 2*k^-1

x = 2*k^-1

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