k=2(4-k)-14

Solution for k=2(4-k)-14 equation:

k=2(4-k)-14

We move all terms to the left:

k-(2(4-k)-14)=0

We add all the numbers together, and all the variables

k-(2(-1k+4)-14)=0


We calculate terms in parentheses: -(2(-1k+4)-14), so:

2(-1k+4)-14

We multiply parentheses

-2k+8-14

We add all the numbers together, and all the variables

-2k-6

Back to the equation:

-(-2k-6)


We get rid of parentheses

k+2k+6=0

We add all the numbers together, and all the variables

3k+6=0

We move all terms containing k to the left, all other terms to the right

3k=-6

k=-6/3

k=-2