k=7/3(2k-1)-12

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Solution for k=7/3(2k-1)-12 equation: 



k=7/3(2k-1)-12

We move all terms to the left:

k-(7/3(2k-1)-12)=0



Domain of the equation: 3(2k-1)-12)!=0

k∈R



We multiply all the terms by the denominator


k*3(2k-1)-12)-(7=0

We add all the numbers together, and all the variables

k*3(2k-1)=0

Wy multiply elements

3k^2(2=0

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