k=7/9k=

Solution for k=7/9k= equation:

k=7/9k=

We move all terms to the left:

k-(7/9k)=0


Domain of the equation: 9k)!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

k-(+7/9k)=0

We get rid of parentheses

k-7/9k=0

We multiply all the terms by the denominator


k*9k-7=0

Wy multiply elements

9k^2-7=0

a = 9; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·9·(-7)
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{7}}{2*9}=\frac{0-6\sqrt{7}}{18}
=-\frac{6\sqrt{7}}{18}
=-\frac{\sqrt{7}}{3}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{7}}{2*9}=\frac{0+6\sqrt{7}}{18}
=\frac{6\sqrt{7}}{18}
=\frac{\sqrt{7}}{3}
$