k=x+3/x-3

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Solution for k=x+3/x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

k = x+3/x-3 // - x+3/x-3

k-x-(3/x)+3 = 0

k-x-3*x^-1+3 = 0

3*x^0-1*x^1-3*x^-1 = 0

(3*x^1-1*x^2-3*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^1-1*x^2-3*x^0) = 0

x^1

3*x-x^2-3 = 0

3*x-x^2-3 = 0

DELTA = 3^2-(-3*(-1)*4)

DELTA = -3

DELTA < 0

x in { } 

x belongs to the empty set

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