l*l-4l-252=0

Solution for l*l-4l-252=0 equation:

l*l-4l-252=0

We add all the numbers together, and all the variables

-4l+l*l-252=0

Wy multiply elements

l^2-4l-252=0

a = 1; b = -4; c = -252;
Δ = b2-4ac
Δ = -42-4·1·(-252)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-32}{2*1}=\frac{-28}{2}
=-14
$
$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+32}{2*1}=\frac{36}{2}
=18
$